Problem of the Week

Updated at Aug 21, 2017 5:11 PM

For this week we've brought you this algebra problem.

How can we compute the factors of \(8{x}^{2}-22x+12\)?

Here are the steps:



\[8{x}^{2}-22x+12\]

1
Find the Greatest Common Factor (GCF).
GCF = \(2\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[2(\frac{8{x}^{2}}{2}+\frac{-22x}{2}+\frac{12}{2})\]

3
Simplify each term in parentheses.
\[2(4{x}^{2}-11x+6)\]

4
Split the second term in \(4{x}^{2}-11x+6\) into two terms.
\[2(4{x}^{2}-3x-8x+6)\]

5
Factor out common terms in the first two terms, then in the last two terms.
\[2(x(4x-3)-2(4x-3))\]

6
Factor out the common term \(4x-3\).
\[2(4x-3)(x-2)\]

Done
Cymath foriOSAndroid