Problem of the Week

Updated at Mar 23, 2026 5:17 PM

How can we compute the factors of \(7{w}^{2}-15w-18\)?

Below is the solution.



\[7{w}^{2}-15w-18\]

1
Split the second term in \(7{w}^{2}-15w-18\) into two terms.
\[7{w}^{2}+6w-21w-18\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[w(7w+6)-3(7w+6)\]

3
Factor out the common term \(7w+6\).
\[(7w+6)(w-3)\]

Done
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