Problem of the Week

Updated at Nov 25, 2024 5:58 PM

This week we have another algebra problem:

How would you find the factors of \(21{v}^{2}-2v-3\)?

Let's start!



\[21{v}^{2}-2v-3\]

1
Split the second term in \(21{v}^{2}-2v-3\) into two terms.
\[21{v}^{2}+7v-9v-3\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[7v(3v+1)-3(3v+1)\]

3
Factor out the common term \(3v+1\).
\[(3v+1)(7v-3)\]

Done
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