Problem of the Week

Updated at Nov 25, 2024 5:58 PM

This week we have another algebra problem:

How would you find the factors of 21v22v321{v}^{2}-2v-3?

Let's start!



21v22v321{v}^{2}-2v-3

1
Split the second term in 21v22v321{v}^{2}-2v-3 into two terms.
21v2+7v9v321{v}^{2}+7v-9v-3

2
Factor out common terms in the first two terms, then in the last two terms.
7v(3v+1)3(3v+1)7v(3v+1)-3(3v+1)

3
Factor out the common term 3v+13v+1.
(3v+1)(7v3)(3v+1)(7v-3)

Done