Problem of the Week

Updated at Feb 24, 2025 4:02 PM

How would you solve 4n23−4n=−4\frac{4{n}^{2}}{3-4n}=-4?

Below is the solution.



4n23−4n=−4\frac{4{n}^{2}}{3-4n}=-4

1
Multiply both sides by 3−4n3-4n.
4n2=−4(3−4n)4{n}^{2}=-4(3-4n)

2
Divide both sides by −4-4.
−n2=3−4n-{n}^{2}=3-4n

3
Move all terms to one side.
n2+3−4n=0{n}^{2}+3-4n=0

4
Factor n2+3−4n{n}^{2}+3-4n.
(n−3)(n−1)=0(n-3)(n-1)=0

5
Solve for nn.
n=3,1n=3,1

Done
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