Problem of the Week

Updated at Dec 9, 2024 9:26 AM

For this week we've brought you this calculus problem.

How can we solve for the derivative of \(\cos{n}+\sec{n}\)?

Here are the steps:



\[\frac{d}{dn} \cos{n}+\sec{n}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dn} \cos{n})+(\frac{d}{dn} \sec{n})\]

2
Use Trigonometric Differentiation: the derivative of \(\cos{x}\) is \(-\sin{x}\).
\[-\sin{n}+(\frac{d}{dn} \sec{n})\]

3
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[\sec{n}\tan{n}-\sin{n}\]

Done
Cymath foriOSAndroid