Problem of the Week

Updated at Jun 7, 2021 3:43 PM

This week we have another algebra problem:

How would you find the factors of 4y2−10y−244{y}^{2}-10y-24?

Let's start!



4y2−10y−244{y}^{2}-10y-24

1
Find the Greatest Common Factor (GCF).
GCF = 22

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
2(4y22+−10y2−242)2(\frac{4{y}^{2}}{2}+\frac{-10y}{2}-\frac{24}{2})

3
Simplify each term in parentheses.
2(2y2−5y−12)2(2{y}^{2}-5y-12)

4
Split the second term in 2y2−5y−122{y}^{2}-5y-12 into two terms.
2(2y2+3y−8y−12)2(2{y}^{2}+3y-8y-12)

5
Factor out common terms in the first two terms, then in the last two terms.
2(y(2y+3)−4(2y+3))2(y(2y+3)-4(2y+3))

6
Factor out the common term 2y+32y+3.
2(2y+3)(y−4)2(2y+3)(y-4)

Done
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