Problem of the Week

Updated at Nov 13, 2017 2:42 PM

How can we find the derivative of x5sinx{x}^{5}\sin{x}?

Below is the solution.



ddxx5sinx\frac{d}{dx} {x}^{5}\sin{x}

1
Use Product Rule to find the derivative of x5sinx{x}^{5}\sin{x}. The product rule states that (fg)=fg+fg(fg)'=f'g+fg'.
(ddxx5)sinx+x5(ddxsinx)(\frac{d}{dx} {x}^{5})\sin{x}+{x}^{5}(\frac{d}{dx} \sin{x})

2
Use Power Rule: ddxxn=nxn1\frac{d}{dx} {x}^{n}=n{x}^{n-1}.
5x4sinx+x5(ddxsinx)5{x}^{4}\sin{x}+{x}^{5}(\frac{d}{dx} \sin{x})

3
Use Trigonometric Differentiation: the derivative of sinx\sin{x} is cosx\cos{x}.
5x4sinx+x5cosx5{x}^{4}\sin{x}+{x}^{5}\cos{x}

Done