Problem of the Week

Updated at Mar 17, 2014 10:11 AM

For this week we've brought you this calculus problem.

How can we solve for the derivative of ln(cosx)\ln{(\cos{x})}?

Here are the steps:



ddxln(cosx)\frac{d}{dx} \ln{(\cos{x})}

1
Use Chain Rule on ddxln(cosx)\frac{d}{dx} \ln{(\cos{x})}. Let u=cosxu=\cos{x}. The derivative of lnu\ln{u} is 1u\frac{1}{u}.
1cosx(ddxcosx)\frac{1}{\cos{x}}(\frac{d}{dx} \cos{x})

2
Use Trigonometric Differentiation: the derivative of cosx\cos{x} is sinx-\sin{x}.
sinxcosx-\frac{\sin{x}}{\cos{x}}

Done