Problem of the Week

Updated at Sep 26, 2022 11:58 AM

This week we have another equation problem:

How would you solve the equation y(4y+2)=72y(4y+2)=72?

Let's start!



y(4y+2)=72y(4y+2)=72

1
Expand.
4y2+2y=724{y}^{2}+2y=72

2
Move all terms to one side.
4y2+2y72=04{y}^{2}+2y-72=0

3
Factor out the common term 22.
2(2y2+y36)=02(2{y}^{2}+y-36)=0

4
Split the second term in 2y2+y362{y}^{2}+y-36 into two terms.
2(2y2+9y8y36)=02(2{y}^{2}+9y-8y-36)=0

5
Factor out common terms in the first two terms, then in the last two terms.
2(y(2y+9)4(2y+9))=02(y(2y+9)-4(2y+9))=0

6
Factor out the common term 2y+92y+9.
2(2y+9)(y4)=02(2y+9)(y-4)=0

7
Solve for yy.
y=92,4y=-\frac{9}{2},4

Done

Decimal Form: -4.5, 4