Problem of the Week

Updated at Sep 9, 2019 1:38 PM

This week we have another calculus problem:

How can we solve for the derivative of \(\sec{n}+6n\)?

Let's start!



\[\frac{d}{dn} \sec{n}+6n\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dn} \sec{n})+(\frac{d}{dn} 6n)\]

2
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[\sec{n}\tan{n}+(\frac{d}{dn} 6n)\]

3
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[\sec{n}\tan{n}+6\]

Done
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