Problem of the Week

Updated at Jul 23, 2018 10:15 AM

This week's problem comes from the algebra category.

How can we factor \(10{x}^{2}-37x+7\)?

Let's begin!



\[10{x}^{2}-37x+7\]

1
Split the second term in \(10{x}^{2}-37x+7\) into two terms.
\[10{x}^{2}-2x-35x+7\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[2x(5x-1)-7(5x-1)\]

3
Factor out the common term \(5x-1\).
\[(5x-1)(2x-7)\]

Done