Problem of the Week

Updated at Jan 29, 2018 1:35 PM

This week's problem comes from the algebra category.

How can we compute the factors of \(2{x}^{2}-15x+7\)?

Let's begin!



\[2{x}^{2}-15x+7\]

1
Split the second term in \(2{x}^{2}-15x+7\) into two terms.
\[2{x}^{2}-x-14x+7\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[x(2x-1)-7(2x-1)\]

3
Factor out the common term \(2x-1\).
\[(2x-1)(x-7)\]

Done