Problem of the Week

Updated at Sep 19, 2016 8:54 AM

To get more practice in calculus, we brought you this problem of the week:

How can we find the derivative of x7sinx{x}^{7}\sin{x}?

Check out the solution below!



ddxx7sinx\frac{d}{dx} {x}^{7}\sin{x}

1
Use Product Rule to find the derivative of x7sinx{x}^{7}\sin{x}. The product rule states that (fg)=fg+fg(fg)'=f'g+fg'.
(ddxx7)sinx+x7(ddxsinx)(\frac{d}{dx} {x}^{7})\sin{x}+{x}^{7}(\frac{d}{dx} \sin{x})

2
Use Power Rule: ddxxn=nxn1\frac{d}{dx} {x}^{n}=n{x}^{n-1}.
7x6sinx+x7(ddxsinx)7{x}^{6}\sin{x}+{x}^{7}(\frac{d}{dx} \sin{x})

3
Use Trigonometric Differentiation: the derivative of sinx\sin{x} is cosx\cos{x}.
7x6sinx+x7cosx7{x}^{6}\sin{x}+{x}^{7}\cos{x}

Done