Problem of the Week

Updated at Feb 24, 2014 5:25 PM

This week's problem comes from the calculus category.

How would you differentiate xlnxx\ln{x}?

Let's begin!



ddxxlnx\frac{d}{dx} x\ln{x}

1
Use Product Rule to find the derivative of xlnxx\ln{x}. The product rule states that (fg)=fg+fg(fg)'=f'g+fg'.
(ddxx)lnx+x(ddxlnx)(\frac{d}{dx} x)\ln{x}+x(\frac{d}{dx} \ln{x})

2
Use Power Rule: ddxxn=nxn1\frac{d}{dx} {x}^{n}=n{x}^{n-1}.
lnx+x(ddxlnx)\ln{x}+x(\frac{d}{dx} \ln{x})

3
The derivative of lnx\ln{x} is 1x\frac{1}{x}.
lnx+1\ln{x}+1

Done