Problem of the Week

Updated at Jan 6, 2014 12:14 PM

To get more practice in calculus, we brought you this problem of the week:

How can we solve for the derivative of \(\ln{(\sec{x})}\)?

Check out the solution below!



\[\frac{d}{dx} \ln{(\sec{x})}\]

1
Use Chain Rule on \(\frac{d}{dx} \ln{(\sec{x})}\). Let \(u=\sec{x}\). The derivative of \(\ln{u}\) is \(\frac{1}{u}\).
\[\frac{1}{\sec{x}}(\frac{d}{dx} \sec{x})\]

2
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[\tan{x}\]

Done
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