Problem of the Week

Updated at Aug 12, 2013 10:11 AM

For this week we've brought you this calculus problem.

How can we solve for the derivative of x7cosx{x}^{7}\cos{x}?

Here are the steps:



ddxx7cosx\frac{d}{dx} {x}^{7}\cos{x}

1
Use Product Rule to find the derivative of x7cosx{x}^{7}\cos{x}. The product rule states that (fg)=fg+fg(fg)'=f'g+fg'.
(ddxx7)cosx+x7(ddxcosx)(\frac{d}{dx} {x}^{7})\cos{x}+{x}^{7}(\frac{d}{dx} \cos{x})

2
Use Power Rule: ddxxn=nxn1\frac{d}{dx} {x}^{n}=n{x}^{n-1}.
7x6cosx+x7(ddxcosx)7{x}^{6}\cos{x}+{x}^{7}(\frac{d}{dx} \cos{x})

3
Use Trigonometric Differentiation: the derivative of cosx\cos{x} is sinx-\sin{x}.
7x6cosxx7sinx7{x}^{6}\cos{x}-{x}^{7}\sin{x}

Done