\[2{x}^{2}-x-1=0\]

1
Split the second term in 2x2x12{x}^{2}-x-1 into two terms.
2x2+x2x1=02{x}^{2}+x-2x-1=0

2
Factor out common terms in the first two terms, then in the last two terms.
x(2x+1)(2x+1)=0x(2x+1)-(2x+1)=0

3
Factor out the common term 2x+12x+1.
(2x+1)(x1)=0(2x+1)(x-1)=0

4
Solve for xx.
x=12,1x=-\frac{1}{2},1

Done

Decimal Form: -0.5, 1

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