Problem of the Week

Updated at Dec 27, 2021 10:25 AM

This week's problem comes from the algebra category.

How would you find the factors of \(28{x}^{2}-41x+15\)?

Let's begin!



\[28{x}^{2}-41x+15\]

1
Split the second term in \(28{x}^{2}-41x+15\) into two terms.
\[28{x}^{2}-20x-21x+15\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[4x(7x-5)-3(7x-5)\]

3
Factor out the common term \(7x-5\).
\[(7x-5)(4x-3)\]

Done