Problem of the Week

Updated at Apr 13, 2020 4:38 PM

This week we have another calculus problem:

How can we solve for the derivative of \(6q+\sec{q}\)?

Let's start!



\[\frac{d}{dq} 6q+\sec{q}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dq} 6q)+(\frac{d}{dq} \sec{q})\]

2
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[6+(\frac{d}{dq} \sec{q})\]

3
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[6+\sec{q}\tan{q}\]

Done
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