Problem of the Week

Updated at Oct 28, 2019 12:04 PM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation 3(x−3)(4x+4)=603(x-3)(4x+4)=60?

Check out the solution below!



3(x−3)(4x+4)=603(x-3)(4x+4)=60

1
Expand.
12x2+12x−36x−36=6012{x}^{2}+12x-36x-36=60

2
Simplify  12x2+12x−36x−3612{x}^{2}+12x-36x-36  to  12x2−24x−3612{x}^{2}-24x-36.
12x2−24x−36=6012{x}^{2}-24x-36=60

3
Move all terms to one side.
12x2−24x−36−60=012{x}^{2}-24x-36-60=0

4
Simplify  12x2−24x−36−6012{x}^{2}-24x-36-60  to  12x2−24x−9612{x}^{2}-24x-96.
12x2−24x−96=012{x}^{2}-24x-96=0

5
Factor out the common term 1212.
12(x2−2x−8)=012({x}^{2}-2x-8)=0

6
Factor x2−2x−8{x}^{2}-2x-8.
12(x−4)(x+2)=012(x-4)(x+2)=0

7
Solve for xx.
x=4,−2x=4,-2

Done
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