Problem of the Week

Updated at Jun 26, 2017 11:10 AM

This week's problem comes from the calculus category.

How would you differentiate x4secx{x}^{4}\sec{x}?

Let's begin!



ddxx4secx\frac{d}{dx} {x}^{4}\sec{x}

1
Use Product Rule to find the derivative of x4secx{x}^{4}\sec{x}. The product rule states that (fg)=fg+fg(fg)'=f'g+fg'.
(ddxx4)secx+x4(ddxsecx)(\frac{d}{dx} {x}^{4})\sec{x}+{x}^{4}(\frac{d}{dx} \sec{x})

2
Use Power Rule: ddxxn=nxn1\frac{d}{dx} {x}^{n}=n{x}^{n-1}.
4x3secx+x4(ddxsecx)4{x}^{3}\sec{x}+{x}^{4}(\frac{d}{dx} \sec{x})

3
Use Trigonometric Differentiation: the derivative of secx\sec{x} is secxtanx\sec{x}\tan{x}.
4x3secx+x4secxtanx4{x}^{3}\sec{x}+{x}^{4}\sec{x}\tan{x}

Done