Problem of the Week

Updated at Nov 21, 2016 1:19 PM

To get more practice in calculus, we brought you this problem of the week:

How would you differentiate 54cosx\frac{5}{4\cos{x}}?

Check out the solution below!



ddx54cosx\frac{d}{dx} \frac{5}{4\cos{x}}

1
Use Constant Factor Rule: ddxcf(x)=c(ddxf(x))\frac{d}{dx} cf(x)=c(\frac{d}{dx} f(x)).
54(ddx1cosx)\frac{5}{4}(\frac{d}{dx} \frac{1}{\cos{x}})

2
Use Chain Rule on ddx1cosx\frac{d}{dx} \frac{1}{\cos{x}}. Let u=cosxu=\cos{x}. Use Power Rule: dduun=nun1\frac{d}{du} {u}^{n}=n{u}^{n-1}.
54×1cos2x(ddxcosx)\frac{5}{4}\times \frac{-1}{\cos^{2}x}(\frac{d}{dx} \cos{x})

3
Use Trigonometric Differentiation: the derivative of cosx\cos{x} is sinx-\sin{x}.
5sinx4cos2x\frac{5\sin{x}}{4\cos^{2}x}

Done