Problem of the Week

Updated at Sep 14, 2015 2:16 PM

For this week we've brought you this calculus problem.

How would you differentiate \(\sec{x}+\sin{x}\)?

Here are the steps:



\[\frac{d}{dx} \sec{x}+\sin{x}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dx} \sec{x})+(\frac{d}{dx} \sin{x})\]

2
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[\sec{x}\tan{x}+(\frac{d}{dx} \sin{x})\]

3
Use Trigonometric Differentiation: the derivative of \(\sin{x}\) is \(\cos{x}\).
\[\sec{x}\tan{x}+\cos{x}\]

Done
Cymath foriOSAndroid