Problem of the Week

Updated at Apr 27, 2015 9:06 AM

For this week we've brought you this calculus problem.

How can we find the derivative of \(\ln{x}\sin{x}\)?

Here are the steps:



\[\frac{d}{dx} \ln{x}\sin{x}\]

1
Use Product Rule to find the derivative of \(\ln{x}\sin{x}\). The product rule states that \((fg)'=f'g+fg'\).
\[(\frac{d}{dx} \ln{x})\sin{x}+\ln{x}(\frac{d}{dx} \sin{x})\]

2
The derivative of \(\ln{x}\) is \(\frac{1}{x}\).
\[\frac{\sin{x}}{x}+\ln{x}(\frac{d}{dx} \sin{x})\]

3
Use Trigonometric Differentiation: the derivative of \(\sin{x}\) is \(\cos{x}\).
\[\frac{\sin{x}}{x}+\ln{x}\cos{x}\]

Done
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