Problem of the Week

Updated at Feb 3, 2014 2:01 PM

For this week we've brought you this calculus problem.

How would you differentiate xcosxx\cos{x}?

Here are the steps:



ddxxcosx\frac{d}{dx} x\cos{x}

1
Use Product Rule to find the derivative of xcosxx\cos{x}. The product rule states that (fg)=fg+fg(fg)'=f'g+fg'.
(ddxx)cosx+x(ddxcosx)(\frac{d}{dx} x)\cos{x}+x(\frac{d}{dx} \cos{x})

2
Use Power Rule: ddxxn=nxn1\frac{d}{dx} {x}^{n}=n{x}^{n-1}.
cosx+x(ddxcosx)\cos{x}+x(\frac{d}{dx} \cos{x})

3
Use Trigonometric Differentiation: the derivative of cosx\cos{x} is sinx-\sin{x}.
cosxxsinx\cos{x}-x\sin{x}

Done