\[{x}^{4}-5{x}^{2}+4\]

1
Ask: Which two numbers add up to 5-5 and multiply to 44?
4-4 and 1-1

2
Rewrite the expression using the above.
(x24)(x21)({x}^{2}-4)({x}^{2}-1)

3
Rewrite x24{x}^{2}-4 in the form a2b2{a}^{2}-{b}^{2}, where a=xa=x and b=2b=2.
(x222)(x21)({x}^{2}-{2}^{2})({x}^{2}-1)

4
Use Difference of Squares: a2b2=(a+b)(ab){a}^{2}-{b}^{2}=(a+b)(a-b).
(x+2)(x2)(x21)(x+2)(x-2)({x}^{2}-1)

5
Rewrite x21{x}^{2}-1 in the form a2b2{a}^{2}-{b}^{2}, where a=xa=x and b=1b=1.
(x+2)(x2)(x212)(x+2)(x-2)({x}^{2}-{1}^{2})

6
Use Difference of Squares: a2b2=(a+b)(ab){a}^{2}-{b}^{2}=(a+b)(a-b).
(x+2)(x2)(x+1)(x1)(x+2)(x-2)(x+1)(x-1)

Done

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