\[60{h}^{2}+280h+45\]

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Find the Greatest Common Factor (GCF).

What is the largest number that divides evenly into

60{h}^{2}

280h

, and

45

It is

5

What is the highest degree of $h$ that divides evenly into

60{h}^{2}

280h

, and

45

It is 1, since

h

is not in every term.

Multiplying the results above,

The GCF is

5

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GCF =

5

Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

5(\frac{60{h}^{2}}{5}+\frac{280h}{5}+\frac{45}{5})

Simplify each term in parentheses.

5(12{h}^{2}+56h+9)

Split the second term in

12{h}^{2}+56h+9

into two terms.

Multiply the coefficient of the first term by the constant term.

12\times 9=108

Ask: Which two numbers add up to

56

and multiply to

108

54

and

2

Split

56h

as the sum of

54h

and

2h

12{h}^{2}+54h+2h+9

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5(12{h}^{2}+54h+2h+9)

Factor out common terms in the first two terms, then in the last two terms.

5(6h(2h+9)+(2h+9))

Factor out the common term

2h+9

5(2h+9)(6h+1)

Done

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