Problem of the Week

Updated at Jul 3, 2023 9:26 AM

For this week we've brought you this algebra problem.

How can we compute the factors of \(25{z}^{2}-40z+12\)?

Here are the steps:



\[25{z}^{2}-40z+12\]

1
Split the second term in \(25{z}^{2}-40z+12\) into two terms.
\[25{z}^{2}-10z-30z+12\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[5z(5z-2)-6(5z-2)\]

3
Factor out the common term \(5z-2\).
\[(5z-2)(5z-6)\]

Done
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