Problem of the Week

Updated at Mar 27, 2023 1:35 PM

This week's problem comes from the algebra category.

How can we compute the factors of \(21{n}^{2}+23n-20\)?

Let's begin!



\[21{n}^{2}+23n-20\]

1
Split the second term in \(21{n}^{2}+23n-20\) into two terms.
\[21{n}^{2}+35n-12n-20\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[7n(3n+5)-4(3n+5)\]

3
Factor out the common term \(3n+5\).
\[(3n+5)(7n-4)\]

Done