Problem of the Week

Updated at Nov 1, 2021 4:12 PM

How can we solve the equation \(\frac{5}{3}(v+2)+4=\frac{32}{3}\)?

Below is the solution.



\[\frac{5}{3}(v+2)+4=\frac{32}{3}\]

1
Simplify  \(\frac{5}{3}(v+2)\)  to  \(\frac{5(v+2)}{3}\).
\[\frac{5(v+2)}{3}+4=\frac{32}{3}\]

2
Subtract \(4\) from both sides.
\[\frac{5(v+2)}{3}=\frac{32}{3}-4\]

3
Simplify  \(\frac{32}{3}-4\)  to  \(\frac{20}{3}\).
\[\frac{5(v+2)}{3}=\frac{20}{3}\]

4
Multiply both sides by \(3\).
\[5(v+2)=\frac{20}{3}\times 3\]

5
Cancel \(3\).
\[5(v+2)=20\]

6
Divide both sides by \(5\).
\[v+2=\frac{20}{5}\]

7
Simplify  \(\frac{20}{5}\)  to  \(4\).
\[v+2=4\]

8
Subtract \(2\) from both sides.
\[v=4-2\]

9
Simplify  \(4-2\)  to  \(2\).
\[v=2\]

Done
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