Problem of the Week

Updated at Apr 12, 2021 12:16 PM

For this week we've brought you this equation problem.

How would you solve the equation 4(45y3)=1254(\frac{4}{5}y-3)=-\frac{12}{5}?

Here are the steps:



4(45y3)=1254(\frac{4}{5}y-3)=-\frac{12}{5}

1
Simplify  45y\frac{4}{5}y  to  4y5\frac{4y}{5}.
4(4y53)=1254(\frac{4y}{5}-3)=-\frac{12}{5}

2
Divide both sides by 44.
4y53=1254\frac{4y}{5}-3=-\frac{\frac{12}{5}}{4}

3
Simplify  1254\frac{\frac{12}{5}}{4}  to  125×4\frac{12}{5\times 4}.
4y53=125×4\frac{4y}{5}-3=-\frac{12}{5\times 4}

4
Simplify  5×45\times 4  to  2020.
4y53=1220\frac{4y}{5}-3=-\frac{12}{20}

5
Simplify  1220\frac{12}{20}  to  35\frac{3}{5}.
4y53=35\frac{4y}{5}-3=-\frac{3}{5}

6
Add 33 to both sides.
4y5=35+3\frac{4y}{5}=-\frac{3}{5}+3

7
Simplify  35+3-\frac{3}{5}+3  to  125\frac{12}{5}.
4y5=125\frac{4y}{5}=\frac{12}{5}

8
Multiply both sides by 55.
4y=125×54y=\frac{12}{5}\times 5

9
Cancel 55.
4y=124y=12

10
Divide both sides by 44.
y=124y=\frac{12}{4}

11
Simplify  124\frac{12}{4}  to  33.
y=3y=3

Done