Problem of the Week

Updated at Apr 27, 2020 2:54 PM

To get more practice in calculus, we brought you this problem of the week:

How can we find the derivative of \(6u+\sec{u}\)?

Check out the solution below!



\[\frac{d}{du} 6u+\sec{u}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{du} 6u)+(\frac{d}{du} \sec{u})\]

2
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[6+(\frac{d}{du} \sec{u})\]

3
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[6+\sec{u}\tan{u}\]

Done
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