Problem of the Week

Updated at Feb 10, 2020 5:21 PM

For this week we've brought you this equation problem.

How can we solve the equation \(4(3-\frac{5}{{q}^{2}})=-8\)?

Here are the steps:



\[4(3-\frac{5}{{q}^{2}})=-8\]

1
Divide both sides by \(4\).
\[3-\frac{5}{{q}^{2}}=-\frac{8}{4}\]

2
Simplify  \(\frac{8}{4}\)  to  \(2\).
\[3-\frac{5}{{q}^{2}}=-2\]

3
Subtract \(3\) from both sides.
\[-\frac{5}{{q}^{2}}=-2-3\]

4
Simplify  \(-2-3\)  to  \(-5\).
\[-\frac{5}{{q}^{2}}=-5\]

5
Multiply both sides by \({q}^{2}\).
\[-5=-5{q}^{2}\]

6
Divide both sides by \(-5\).
\[1={q}^{2}\]

7
Take the square root of both sides.
\[\pm \sqrt{1}=q\]

8
Simplify  \(\sqrt{1}\)  to  \(1\).
\[\pm 1=q\]

9
Switch sides.
\[q=\pm 1\]

Done
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