Problem of the Week

Updated at Jan 6, 2020 11:49 AM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation \(\frac{{m}^{2}+2}{2}-3=6\)?

Check out the solution below!



\[\frac{{m}^{2}+2}{2}-3=6\]

1
Simplify  \(\frac{{m}^{2}+2}{2}\)  to  \(1+\frac{{m}^{2}}{2}\).
\[1+\frac{{m}^{2}}{2}-3=6\]

2
Simplify  \(1+\frac{{m}^{2}}{2}-3\)  to  \(\frac{{m}^{2}}{2}-2\).
\[\frac{{m}^{2}}{2}-2=6\]

3
Add \(2\) to both sides.
\[\frac{{m}^{2}}{2}=6+2\]

4
Simplify  \(6+2\)  to  \(8\).
\[\frac{{m}^{2}}{2}=8\]

5
Multiply both sides by \(2\).
\[{m}^{2}=8\times 2\]

6
Simplify  \(8\times 2\)  to  \(16\).
\[{m}^{2}=16\]

7
Take the square root of both sides.
\[m=\pm \sqrt{16}\]

8
Since \(4\times 4=16\), the square root of \(16\) is \(4\).
\[m=\pm 4\]

Done
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