Problem of the Week

Updated at Nov 25, 2019 11:37 AM

How would you find the factors of 2z217z+302{z}^{2}-17z+30?

Below is the solution.



2z217z+302{z}^{2}-17z+30

1
Split the second term in 2z217z+302{z}^{2}-17z+30 into two terms.
2z25z12z+302{z}^{2}-5z-12z+30

2
Factor out common terms in the first two terms, then in the last two terms.
z(2z5)6(2z5)z(2z-5)-6(2z-5)

3
Factor out the common term 2z52z-5.
(2z5)(z6)(2z-5)(z-6)

Done