Problem of the Week

Updated at Jan 28, 2019 4:31 PM

For this week we've brought you this equation problem.

How would you solve the equation 4(z5+2)×5z=124(\frac{z}{5}+2)\times \frac{5}{z}=12?

Here are the steps:



4(z5+2)×5z=124(\frac{z}{5}+2)\times \frac{5}{z}=12

1
Multiply both sides by zz.
20(z5+2)=12z20(\frac{z}{5}+2)=12z

2
Expand.
4z+40=12z4z+40=12z

3
Subtract 4z4z from both sides.
40=12z4z40=12z-4z

4
Simplify  12z4z12z-4z  to  8z8z.
40=8z40=8z

5
Divide both sides by 88.
408=z\frac{40}{8}=z

6
Simplify  408\frac{40}{8}  to  55.
5=z5=z

7
Switch sides.
z=5z=5

Done