Problem of the Week

Updated at Oct 15, 2018 3:04 PM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation (y−3)2×54y=0{(y-3)}^{2}\times \frac{5}{4y}=0?

Check out the solution below!



(y−3)2×54y=0{(y-3)}^{2}\times \frac{5}{4y}=0

1
Use this rule: a×bc=abca \times \frac{b}{c}=\frac{ab}{c}.
(y−3)2×54y=0\frac{{(y-3)}^{2}\times 5}{4y}=0

2
Regroup terms.
5(y−3)24y=0\frac{5{(y-3)}^{2}}{4y}=0

3
Multiply both sides by 4y4y.
5(y−3)2=05{(y-3)}^{2}=0

4
Divide both sides by 55.
(y−3)2=0{(y-3)}^{2}=0

5
Take the square root of both sides.
y−3=0y-3=0

6
Add 33 to both sides.
y=3y=3

Done
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