Problem of the Week

Updated at Apr 30, 2018 5:17 PM

How can we compute the factors of \(8{x}^{2}-18x+9\)?

Below is the solution.



\[8{x}^{2}-18x+9\]

1
Split the second term in \(8{x}^{2}-18x+9\) into two terms.
\[8{x}^{2}-6x-12x+9\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[2x(4x-3)-3(4x-3)\]

3
Factor out the common term \(4x-3\).
\[(4x-3)(2x-3)\]

Done
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