Problem of the Week

Updated at Dec 25, 2017 9:49 AM

To get more practice in algebra, we brought you this problem of the week:

How would you find the factors of \(14{x}^{2}-42x+28\)?

Check out the solution below!



\[14{x}^{2}-42x+28\]

1
Find the Greatest Common Factor (GCF).
GCF = \(14\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[14(\frac{14{x}^{2}}{14}+\frac{-42x}{14}+\frac{28}{14})\]

3
Simplify each term in parentheses.
\[14({x}^{2}-3x+2)\]

4
Factor \({x}^{2}-3x+2\).
\[14(x-2)(x-1)\]

Done
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