Problem of the Week

Updated at Dec 4, 2017 9:13 AM

This week we have another algebra problem:

How would you find the factors of \(7{x}^{2}-41x+30\)?

Let's start!



\[7{x}^{2}-41x+30\]

1
Split the second term in \(7{x}^{2}-41x+30\) into two terms.
\[7{x}^{2}-6x-35x+30\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[x(7x-6)-5(7x-6)\]

3
Factor out the common term \(7x-6\).
\[(7x-6)(x-5)\]

Done