\[7{x}^{2}+10x+3=0\]

1
Split the second term in 7x2+10x+37{x}^{2}+10x+3 into two terms.
7x2+7x+3x+3=07{x}^{2}+7x+3x+3=0

2
Factor out common terms in the first two terms, then in the last two terms.
7x(x+1)+3(x+1)=07x(x+1)+3(x+1)=0

3
Factor out the common term x+1x+1.
(x+1)(7x+3)=0(x+1)(7x+3)=0

4
Solve for xx.
x=1,37x=-1,-\frac{3}{7}

Done

Decimal Form: -1, -0.428571

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