Problem of the Week

Updated at May 4, 2020 4:14 PM

To get more practice in equation, we brought you this problem of the week:

How would you solve 2(3−z)3−z2=2\frac{2(3-z)}{3-{z}^{2}}=2?

Check out the solution below!



2(3−z)3−z2=2\frac{2(3-z)}{3-{z}^{2}}=2

1
Multiply both sides by 3−z23-{z}^{2}.
2(3−z)=2(3−z2)2(3-z)=2(3-{z}^{2})

2
Cancel 22 on both sides.
3−z=3−z23-z=3-{z}^{2}

3
Cancel 33 on both sides.
−z=−z2-z=-{z}^{2}

4
Move all terms to one side.
z−z2=0z-{z}^{2}=0

5
Factor out the common term zz.
z(1−z)=0z(1-z)=0

6
Solve for zz.
z=0,1z=0,1

Done
Cymath foriOSAndroid