Problem of the Week

Updated at Mar 16, 2020 8:57 AM

How can we factor \(5{p}^{2}+23p-42\)?

Below is the solution.



\[5{p}^{2}+23p-42\]

1
Split the second term in \(5{p}^{2}+23p-42\) into two terms.
\[5{p}^{2}+30p-7p-42\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[5p(p+6)-7(p+6)\]

3
Factor out the common term \(p+6\).
\[(p+6)(5p-7)\]

Done
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