Problem of the Week

Updated at Aug 19, 2019 8:16 AM

For this week we've brought you this equation problem.

How would you solve the equation (p−3)2+23=23\frac{{(p-3)}^{2}+2}{3}=\frac{2}{3}?

Here are the steps:



(p−3)2+23=23\frac{{(p-3)}^{2}+2}{3}=\frac{2}{3}

1
Multiply both sides by 33.
(p−3)2+2=23×3{(p-3)}^{2}+2=\frac{2}{3}\times 3

2
Cancel 33.
(p−3)2+2=2{(p-3)}^{2}+2=2

3
Cancel 22 on both sides.
(p−3)2=0{(p-3)}^{2}=0

4
Take the square root of both sides.
p−3=0p-3=0

5
Add 33 to both sides.
p=3p=3

Done
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