Problem of the Week

Updated at Jun 10, 2019 10:32 AM

How can we compute the factors of \(15{q}^{2}-q-28\)?

Below is the solution.



\[15{q}^{2}-q-28\]

1
Split the second term in \(15{q}^{2}-q-28\) into two terms.
\[15{q}^{2}+20q-21q-28\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[5q(3q+4)-7(3q+4)\]

3
Factor out the common term \(3q+4\).
\[(3q+4)(5q-7)\]

Done
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