Problem of the Week

Updated at Dec 31, 2018 4:43 PM

This week we have another equation problem:

How would you solve the equation 4t−35+2=235\frac{4t-3}{5}+2=\frac{23}{5}?

Let's start!



4t−35+2=235\frac{4t-3}{5}+2=\frac{23}{5}

1
Subtract 22 from both sides.
4t−35=235−2\frac{4t-3}{5}=\frac{23}{5}-2

2
Simplify  235−2\frac{23}{5}-2  to  135\frac{13}{5}.
4t−35=135\frac{4t-3}{5}=\frac{13}{5}

3
Multiply both sides by 55.
4t−3=135×54t-3=\frac{13}{5}\times 5

4
Cancel 55.
4t−3=134t-3=13

5
Add 33 to both sides.
4t=13+34t=13+3

6
Simplify  13+313+3  to  1616.
4t=164t=16

7
Divide both sides by 44.
t=164t=\frac{16}{4}

8
Simplify  164\frac{16}{4}  to  44.
t=4t=4

Done
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