Problem of the Week

Updated at Nov 27, 2017 9:19 AM

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Mar 24, 2025

To get more practice in algebra, we brought you this problem of the week:

How would you find the factors of $7{x}^{2}+11x-6$ ?

Check out the solution below!

7{x}^{2}+11x-6

Split the second term in

7{x}^{2}+11x-6

into two terms.

Multiply the coefficient of the first term by the constant term.

7\times -6=-42

Ask: Which two numbers add up to

11

and multiply to

-42

14

and

-3

Split

11x

as the sum of

14x

and

-3x

7{x}^{2}+14x-3x-6

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7{x}^{2}+14x-3x-6

Factor out common terms in the first two terms, then in the last two terms.

7x(x+2)-3(x+2)

Factor out the common term

x+2

(x+2)(7x-3)

Done