Problem of the Week

Updated at Jun 19, 2017 9:48 AM

This week we have another calculus problem:

How can we find the derivative of \(\sin{x}+\tan{x}\)?

Let's start!



\[\frac{d}{dx} \sin{x}+\tan{x}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dx} \sin{x})+(\frac{d}{dx} \tan{x})\]

2
Use Trigonometric Differentiation: the derivative of \(\sin{x}\) is \(\cos{x}\).
\[\cos{x}+(\frac{d}{dx} \tan{x})\]

3
Use Trigonometric Differentiation: the derivative of \(\tan{x}\) is \(\sec^{2}x\).
\[\cos{x}+\sec^{2}x\]

Done
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