Reference
Practice
Premium
Log In
English
English ✔
Español
日本語
简体中文
繁體中文
x
3
−
1
x
+
2
\frac{{x}^{3}-1}{x+2}
x
+
2
x
3
−
1
+
−
.
ln
>
<
×
÷
/
log
≥
≤
(
)
log
x
=
%
Choose Topic
Examples
"(x+1)/2+4=7"
"factor x^2+5x+6"
"integrate cos(x)^3"
More »
pd((x^3-1)/(x+2))
polynomial division (x^3-1)/(x+2)
\frac{{x}^{3}-1}{x+2}
1
Polynomial Division: Divide
x
3
−
1
{x}^{3}-1
x
3
−
1
by
x
+
2
x+2
x
+
2
.
x
2
x^2
x
2
−
2
x
-2x
−
2
x
4
4
4
x
+
2
x+2
x
+
2
x
3
x^3
x
3
−
1
-1
−
1
x
3
x^3
x
3
2
x
2
2x^2
2
x
2
−
2
x
2
-2x^2
−
2
x
2
−
1
-1
−
1
−
2
x
2
-2x^2
−
2
x
2
−
4
x
-4x
−
4
x
4
x
4x
4
x
−
1
-1
−
1
4
x
4x
4
x
8
8
8
−
9
-9
−
9
2
Rewrite the expression using the above.
x
2
−
2
x
+
4
−
9
x
+
2
{x}^{2}-2x+4-\frac{9}{x+2}
x
2
−
2
x
+
4
−
x
+
2
9
Done
x^2-2*x+4-9/(x+2)
Like this solution? Share it!
Copy Link
How can we make this solution more helpful?