\[\frac{d}{dx} \csc{x}\cot{x}\]
1
Use Product Rule to find the derivative of csc⁡xcot⁡x\csc{x}\cot{x}. The product rule states that (fg)′=f′g+fg′(fg)'=f'g+fg'.
(ddxcsc⁡x)cot⁡x+csc⁡x(ddxcot⁡x)(\frac{d}{dx} \csc{x})\cot{x}+\csc{x}(\frac{d}{dx} \cot{x})

2
Use Trigonometric Differentiation: the derivative of csc⁡x\csc{x} is −csc⁡xcot⁡x-\csc{x}\cot{x}.
−csc⁡xcot⁡2x+csc⁡x(ddxcot⁡x)-\csc{x}\cot^{2}x+\csc{x}(\frac{d}{dx} \cot{x})

3
Use Trigonometric Differentiation: the derivative of cot⁡x\cot{x} is −csc⁡2x-\csc^{2}x.
−csc⁡xcot⁡2x−csc⁡3x-\csc{x}\cot^{2}x-\csc^{3}x

Done
Copy Link
How can we make this solution more helpful?
Cymath foriOSAndroid